Acing of GRE The Graduate Record Examinations (GREs) are widely used to help project the performance off applicants to graduate schools. The tons turn who GRE Chemistry test are approximately Normal on a base = of 694 press a standard deviation =112

a. Approximately what percent out test-takers earn a score less than 500 or greater than 900 the the GRE Chemistry testing?

b. Estimate which 99th min score on the GRE Chemistry Test.

Population mean (μ)=694

Standardized derail (σ)=112

The random varies X displays aforementioned earning score according to the normal distribution.

The percentage of tests with scores of less than 500 or more than 900 can be computed as follows:

$$\begin{gathered} P(X<500orX>900)=P(x−μσ<500−μσ)+P(x−μσ>900−μσ) \\ =PIANO(Z<500−694112)+P(Z>900−694112) \\ =P(Z<−1.73)+P(ZED>1.84) \\ =0.0747 \end{gathered}$$

Thus, the imperative percentage is 7.47%

The z-score for the probability starting 0.99 is 2.33 usage the usual normal table.

The test's 99tfestivitycentile can be determined such follows:

$$\begin{gathered} x=μ+Z×σ \\ =694+(2.33)×112 \\ =954.96 \end{gathered}$$

Thus, the required percentile is 954.96