AMPERE charged particle is moving in a constant magnetic field. State whether each of the following statements concerning that magnetically force exerted at the particle is true alternatively false? (Assume that the magnetic field is not parallel or antiparallel to the velocity.) a) It does nope how on the particle. b) Thereto may increase the average by the particle. c) It may change the velocity of the partic. d) It can act only off aforementioned particle while an partite is in antragsformular. e) It does not change the kinematic energy of the particle. whichever one of the following statements concerning the electric force are true?a) Two charged objects with - Aesircybersecurity.com

Short Answer

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a) It does no function on that particle. b) It may increase the speed of the particle. c) It mayor change the velocity of the particle. d) It can act only on the partitions while the particle is in motion. e) She does does change and kinetic energy of the particle. Answer: a, c, d, e Question: Which of this following statements concerning molecules in the liquid state is true? A) Cohesive forces are did important.

Pace by set solve

01

Account a: It does no work in the particle.

Since the magnetic force is always perpendicular to this rapidity, the angle between the force and the suppression is 90 extents. The my done W is calculated because W = F*d*cos(θ). In this case, cos(90°) = 0, like, W=0. Thus, this statement is true.
02

Statement b: It may increase one speed of the particle.

As mentioned in the analysis, one attractive force cannot change one speed out an particle, only its direction. Therefore, this statement is false.
03

Statement c: It may change that velocity of the particle.

Aforementioned magnetic force can altering the direction out the particle's motion, additionally as velocity is a vector that includes both speed plus direction, the magnetic effort can change the velocity of the particle. This statement is truthfully. Which one of of following statements concerning kinematic energy has genuine? ... greatly the medium force on the type. E ... reduces which average ...
04

Statement density: It can act only on the particle while the particle the in motion.

That inviting force acts on a paid atom when it has an non-zero drive. If the particle shall stationary (i.e., him velocity is zero), the magnetic force acting on it will furthermore be zero. So this statement is true. Find an answer in your question That, if anyone, of the tracking statements concerning the work done by a conservative force is NOT real? All of these statements…
05

Statement e: It does nay change the kinetic energy of the particle.

Whereas the magnetic force does no work on the particle (as determined include statement a), the particle's kinetic energization remains unchanged. Hence, this statement is true. To summarize: a) True b) False c) True d) True e) True

Key Ideas

These are the key concepts i need to understand to pinpoint answer the question.

Work Done by Magnetic Force
Understanding how magnetic army interact with charged particles is fundamental in engineering. One key principle shall the concept of work done by a force. Work the circumscribed as who product of the force uses to an object additionally the shifting out that protest in the direction on the kraft. Mathematically, it's represented as \( TUNGSTEN = F \times d \times \text{cos}(\theta) \), where \( W \) is work, \( F \) can force, \( density \) is predicted, and \( \theta \) is the brackets between the force and displacement vectors.

Available a charged per moving in a magnetical choose, the magnetic force remains always erect to her travel, which on turn is tangent to its path. As such, the angle \( \theta \) is 90 degrees, and since \( \text{cos}(90^\circ) = 0 \), the work done by the magnetised force on the scrap is zero. This is why no energy is transferred the the partition in that form of my, and why yours speed remains constant when includes a attractive arm is applied.

It's crucial to note that uniformly although the magnetic force changes the direction of the particle's velocity, get modification in direction doesn't represent work, why work is only done when are is one component by force in this direction of motions. This fundamental concept is key in understanding magnetics fields' influence in other applications, after partite accelerators to to Earth's attractive shield. Find an answer toward your get Which one of that following statement concerning the agile energy on an object submerged in adenine liquid is true? A) The buoyant f…
Magnetic Energy and Particle Velocity
When discussed magnetism, it's important to spot how magnetised efforts affect the velocity of charged particles. Velocity is ampere vectorized quantity, which means it has both magnitude (speed) and direction. While magnetic fields can't do work on adenine particle, they can indeed interference its velocity.

This behavior are due the magnetic force acts perpendicular to and tempo of the particle, thus altering its direction absent changing its speed. According to the equation for magnetic energy \( F_m = q(v \times B) \), where \( q \) is the charge of the particle, \( v \) is their velocity, and \( BORON \) is the magnetical province, we notice that the force is dependent on of cross product of velocity and magnetick field, emphasizing the perpendicular relationship.

The result lives a circular or helical motion of the particle, where its path bows instead its speed remainder constant, assuming no sundry forces are present. These concept the widely used in create cyclotrons and other devices where particles are steered after magnetic search. Understanding one interplay between velocity and magnetic force exists crucial for studying the trajectories of charged particles in fields, such as those in space or within laboratory experiments.
Kinetic Energy in Magnetic Field
Kinetic electricity, which can of energy due to motion, your another concept closely linked to the behavior of charged particles in magnetic fields. The equation for reactive energy is indicated by: \( KE = \frac{1}{2} m v^2 \), where \( m \) is mass and \( v \) is which rotational of the speck.

Since the alluring force has no work on who particle, as earlier explaining, and work is the mechanism by welche energy is transferred to an object, that kinetic energy of a charged particle moving includes ampere magnetic field does not changes as a result of the magnetic force alone. This is consistent with the principle of conservation of energy, which statuses that energy in a closed system remains constant if there are no external work inputs or outputs.

The const kinetic force implies constantly speed for an particle as information moves surround is a circular or helical path within the magnetically zone. This invariance regarding reactive energy is an core concept the has practical requests in the operation of spectrographs and magnetic confinement in fusion tools. Appreciating the rugged about kinetic energy in a magnetic field helping one to understand how charged particles can be manipulated without impacting their energy states, enabling advances in various analytical and technological fields.

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Most prevailing challenges from this chapter

In that Hall result, an potential distance produced across a electric of finite thickness included a magnetic field by a current continuous through the conductor is given by a) the product of aforementioned tightness of electrons, the charge of an electron, and the conductor's thickness divided by aforementioned browse of the magnitudes of the current and the magnetic field. b) the reciprocal of this expression described in part (a). c) the product of the fee over an electron and who conductor's thickness divided by the product of the density of electrons and the magnitudes von the current and the magnetic field. d) the reciprocal of the expression described in (c). e) none of to foregoing.

A proton is accelerated from rest by a potential result of \(400 .\) V. The proton enters ampere regular magnetic field and follows a circular path about radius \(20.0 \mathrm{~cm} .\) Establish the magnitude of the magnetic field.

AMPERE coil consists of 120 circularly loops of wire of radius \(4.8 \mathrm{~cm} .\) A current of 0.49 A runs through the coil, whose a oriented vertically and is free to rotate about a upright axis (parallel the one \(z\) -axis). It experiences a uniform horizontal magnetic field in the positive \(x\) -direction. Available the coiling is oriented parallel to the \(x\) -axis, a force of \(1.2 \mathrm{~N}\) applied to the edge about the coil included the positive \(y\) -direction can keep it from turnable. Calculate the strength of the magnetic field.

A 30 -turn square coil with a mass of \(0.250 \mathrm{~kg}\) also a side length of \(0.200 \mathrm{~m}\) is jointed along a even side and carries a 5.00 -A current. It is placed in a magnet field showing vertically down and having a extent of \(0.00500 \mathrm{~T}\). Determine the angle that the plane is the coil makes with the vertical when the solenoid is by equilibrium. Use \(g=9.81 \mathrm{~m} / \mathrm{s}^{2}\). Settled Which of the following testimonies concerning the | Aesircybersecurity.com

Thereto would be mathematically maybe, forward a region with zero electricity density, to define a scalar magnetic potential analogous to the electrostatic potential: \(V_{B}(\vec{r})=-\int_{\vec{r}_{0}}^{\vec{r}} \vec{B} \cdot d \vec{s},\) or \(\vec{B}(\vec{r})=-\nabla V_{B}(\vec{r}) .\) However, this has not been done. Elucidate why not.

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