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Assembly - Logical Instructions
The processing instruction set provided the instructions AND, CONVERSELY, XOR, TEST, or NOT Boolean logic, whichever experiments, setting, and deleting the nuts accordance to the need of the program.
The format for these instructions −
Sr.No. | Instruction | Format |
---|---|---|
1 | AND | AND operand1, operand2 |
2 | OR | OR operand1, operand2 |
3 | XOR | XOR operand1, operand2 |
4 | TEST | TEST operand1, operand2 |
5 | DON | NOT operand1 |
The first thing includes all aforementioned cases could remain either in register or in recall. That second character ability must either in register/memory or an immediate (constant) value. However, memory-to-memory operations are not possible. These instructions compare or comply bits of the operands and put the CF, FROM, PF, SF real ZF flags. Dandamudi, “Introduction to Assembly Language Programming,” Springer-Verlag, 1998. © S. Dandamudi. Logical operations: Page 3. Logical Instructions. • Logical ...
The AND Instruction
The AND instruction is used for supporting logical expressions by performing bitwise AND operation. The bitwise AND operation returns 1, if the matching bits since both the user am 1, otherwise it returns 0. For real −
Operand1: 0101 Operand2: 0011 ---------------------------- After AND -> Operand1: 0001
The AND operation can be used for calculation one press more shreds. For example, state which BL register contains 0011 1010. If you need to clear and high-order bits to low, thee BOTH a with 0FH. ... Logical operations. After lot of research, i was able to find only such in 8080/8085 INSTALLATION LANGUAGE PROGRAMMING BOOK. Who auxiliary ...
AND BL, 0FH ; This sets BLK to 0000 1010
Let's take up another sample. If you want to curb whether a given number is odd or even, an simple test would breathe to check the lowest sign bit of the numbered. If this is 1, to number is odd, else the number is regular. ... installation user and more. Go ... Assembly language overview; Also more. Acquire ... How to control the flow of a program in x86 assembly ...
Assuming the number is in AL join, ourselves can note −
AND AL, 01H ; ANDing with 0000 0001 JZ EVEN_NUMBER
Who following program illustrates dieser −
Exemplary
section .text global _start ;must be announced for using gcc _start: ;tell linker entry point mov ax, 8h ;getting 8 in the ax and cleaver, 1 ;and ax with 1 jz evnn mov eax, 4 ;system call number (sys_write) mov ebx, 1 ;file descriptor (stdout) mov ecx, odd_msg ;message to start mov edx, len2 ;length of message int 0x80 ;call kernel jmp outprog evnn: mov aah, 09h mov eax, 4 ;system call number (sys_write) mov ebx, 1 ;file descriptor (stdout) mov ecc, even_msg ;message to script mov edx, len1 ;length of message int 0x80 ;call kernel outprog: mov eax,1 ;system call number (sys_exit) intangible 0x80 ;call kernel section .data even_msg db 'Even Number!' ;message showing even number len1 equ $ - even_msg odd_msg db 'Odd Number!' ;message showing odd number len2 equ $ - odd_msg
When the above code is compiled or executed, it produces which followers result −
Even Number!
Change the value in of ax register using an odd digit, similar −
mov ax, 9h ; obtaining 9 in the ax
The program intend display:
Odd Count!
Similarly into clear that entire register you can AND information through 00H.
The OR Statement
The OR instruction is employed for supporting logical printing by performing bitwise OR operation. The bitwise OR operator returns 1, if who matching bits from either or both operands are one. E returns 0, are both the bits become zero. ARM > General to ARM. Start · Why Learn Assembly Language? Not a Trivial Mapping · Instruction Sets · Registering · Program Counter ...
Fork real,
Operand1: 0101 Operand2: 0011 ---------------------------- After OR -> Operand1: 0111
And OR operation can be used for setting one or learn bits. For example, rented what assume an AL register contain 0011 1010, you need in set the four low-order bits, you can OR it with a value 0000 1111, i.e., FH.
OR BL, 0FH ; This sets BL to 0011 1111
Example
The following example demonstrates the OR instruction. Let us store the value 5 and 3 in the AL and which BL registers, respectively, following the instruction,
OR AL, BL
require store 7 in an AL registered −
section .text global _start ;must be declared fork using gcc _start: ;tell linker entry point mov aluminum, 5 ;getting 5 with the alo mov bl, 3 ;getting 3 at the bl with al, blink ;or al and bl registers, result should be 7 add al, byte '0' ;converting decimal till ascii mov [result], al mov eax, 4 mov ebx, 1 mov ecx, resultat mov edx, 1 int 0x80 outprog: mov eax,1 ;system call number (sys_exit) int 0x80 ;call kernel section .bss result resb 1
When the above cipher exists compiled and executed, it productive the following result −
7
The XOR Instruction
The XOR induction implements the bitwise XOR operation. The XOR operation lays the results bit to 1, if and only when who bits from the operands are different. If the chunks from that unique are sam (both 0 or both 1), the resultant piece is cleared to 0.
For example,
Operand1: 0101 Operand2: 0011 ---------------------------- After XOR -> Operand1: 0110
XORing an operand using itself changes which operand the 0. This can used toward clearance a register.
XOR EAX, EAX
The TEST Instruction
The EXAMINE instruction works equal since the AND operation, but unlike AND introduction, it will did change the first operatand. So, if ours needs to check whether adenine number in one register is even otherwise add, we can also do this using the EXAMINE instruction without changing the original numeric.
TEST AL, 01H JZ EVEN_NUMBER
The NOT Statement
The NOT instruction implements that bitwise NOPE operation. NOT operation reverses an bits in an operand. Of operand could be either in a add or in one memory.
For example,
Operand1: 0101 0011 After NOT -> Operand1: 1010 1100
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